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전기자기학 리포트 chapter01 7th solution

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전기자기학 리포트 chapter01 7th solution
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전기자기학 리포트 chapter01 7th solution

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설명

CHAPTER 1 1.1. Given the vectors M 〓 10ax + 4ay 8az and N 〓 8ax + 7ay 2az , nd: a) a unit vector in the direction of M + 2N. M + 2N 〓 10ax 4ay + 8az + 16ax + 14ay 4az 〓 (26, 10, 4) Thus a〓 b) the magnitude of 5ax + N 3M: (5, 0, 0) + (8, 7, 2) (30, 12, 24) 〓 (43, 5, 22), and |(43, 5, 22)| 〓 48.6. c) |M||2N|(M + N): |(10, 4, 8)||(16, 14, 4)|(2, 11, 10) 〓 (13.4)(21.6)(2, 11, 10) 〓 (580.5, 3193, 2902) 1.2. The three vertices of a triangle are located at A(1, 2, 5), B(4, 2, 3), and C(1, 3, 2). ...

CHAPTER 1 1.1. Given the vectors M 〓 10ax + 4ay 8az and N 〓 8ax + 7ay 2az , nd: a) a unit vector in the direction of M + 2N. M + 2N 〓 10ax 4ay + 8az + 16ax + 14ay 4az 〓 (26, 10, 4) Thus a〓 b) the magnitude of 5ax + N 3M: (5, 0, 0) + (8, 7, 2) (30, 12, 24) 〓 (43, 5, 22), and |(43, 5, 22)| 〓 48.6. c) |M||2N|(M + N): |(10, 4, 8)||(16, 14, 4)|(2, 11, 10) 〓 (13.4)(21.6)(2, 11, 10) 〓 (580.5, 3193, 2902) 1.2. The three vertices of a triangle are located at A(1, 2, 5), B(4, 2, 3), and C(1, 3, 2). a) Find the length of the perimeter of the triangle: Begin with AB 〓 (3, 4, 8),√ 〓 (5, 5, 1), BC and CA 〓 (2, √ 7). Then the perimeter will be 〓 |AB| + |BC| + |CA| 〓 9 + 16 + 64 + 1, √ 25 + 25 + 1 + 4 + 1 + 49 〓 23.9. b) Find a unit vector that is directed from the midpoint of the side AB to the midpoint of side BC: The vector from the origin to the midpoint of AB is MAB 〓 1 (A + B) 〓 1 (5ax + 2az ). 2 2 The vector from the origin to the midpoint of BC is MBC 〓 1 (B + C) 〓 1 (3ax + ay 5az ). 2 …(省略)


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